piclist 2017\09\06\085006a >
Thread: Division routines.
face BY : Bob Ammerman email (remove spam text)

I am pretty sure something like the following will work...

Let's say you have a number of bits 'N', typically 8 or 16.

Then, many division routines will have a dividend of 2N bits, and a divisor
of N bits.

So, say you want to divide a N-bit number by another N-bit number with an
implied binary point on the left...

Simply extend your N-bit dividend by N zeros on the right and do the

~ Bob Ammerman
RAm Systems

> {Original Message removed}
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In reply to: <59AEF194.4050105@narwani.org>
See also: www.piclist.com/techref/microchip/math/index.htm?key=division
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