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>Earlier in this thread, the most simple (IMO)) proof that

>0.999(Repeating) = 1 was shown using no magic, mirrors or divides by 0.

> There are 3 thirds in a whole (ie 3*(1/3) = 1)

> and, 1/3 = 0.33333333(repeating forever) (divide it out and see!)

> Multiply that by 3 and get 0.99999999(repeating forever) (try it!)

> Therefore 1 = 0.99999999(repeating forever)

>It may be uncomfortable, but it is true!

>Show me any flaw, trick, or error in this example.

It seems to be something like "angel's gender" but let's revise it.

When you part one something MATERIAL (numbers aren't material, they just TRY to represent it), you get three thirds. One equals another. That's ok.

When you divide the number one, by three, you get ALMOST three equal parts. ALMOST because a calculator cannot represent the part who tend to infinity. If you divide something physical, you can get all three parts with the same volume or weight. But a calculator cannot represent this.

When you bring these three parts togheter (ops, where is my english lexican?) it becomes 1 again. But in a calculator, that ROUND NUMBERS PER SE, it will not bring you the same result. It's valid for any calcule that brings the "dizima periodica" (anyone who speaks portuguese, can tell me how we say this expression in english? It means the infinite .33333333 of the 1/3), because a calculator has a limit of HOW FAR can it store numbers.

So, I think it's nice to speak that 0.9999999999999 TENDS to 1. But it can never be 1.

And of course, In my HP48 I trust :o) And it gives me 0.99999999999999 when I multiply 0.33333333333 x 3 :o)

---8<---Corte aqui---8<----

Alexandre Souza

spamtaito@spam@spam_OUTterra.com.br

http://planeta.terra.com.br/lazer/pinball/

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