piclist 2001\02\26\073600a >
Thread: Formula for unbalanced bridge Rx-> V
face BY : mikespamBeGone@whitewing.co.uk

Any maths wizards out there....?
Given a conventional resistance bridge :
R1  R2
+----|--- Vout (differential)
|    +---
R3  Rx

What is the formula to determine Rx (Or, better,  the ratio Rx/R3)
given the ratio Vout/Vin. R1=R2 if that makes anything easier.

My algebra isn't quite up to juggling it round - I got as far as the
following before my brain started to hurt :
Rx/(Rx+R2) = V-(R3/(R1+R3)
where V is the ratio Vout/Vin

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Subject (change) Formula for unbalanced bridge Rx-> V

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