piclist 2001\02\10\100447a >
Thread: How does one measure power in an ultrasonic transducer??
face BY : mike@spamwhitewing.co.uk

On Fri, 9 Feb 2001 18:01:41 -0500, you wrote:

{Quote hidden}

Most piezos are basically capacitors, and driving them is basically
about charging and discharging that capacitance, so harmonic content
is not usually an issue - the capacitance and mechanical inertia takes
care of it (this may be less the case for low-mass ultrasonic units).
Max output usually happens if you charge and discharge the piezo
capacitance as quickly as possible, i.e. with a square wave. The
current waveform will tend to look pretty spiky, as it would driving a
pure capacitance. Square wave drive also means you lose less power in
the driver.  
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<uaca8t8k59f03nc42buc6gv353rg1jre6j@4ax.com> quoted-printable

In reply to: <001b01c092ec$43cd9ea0$260bf6cd@pc>
See also: www.piclist.com/techref/power.htm?key=power
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Subject (change) How does one measure power in an ultrasonic transducer??

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