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Thread
'Current to voltage- anyone know of an IC?'
1997\07\02@054654
by
Hennie Swanepoel
I am thinking of using a microcontroller (perhaps a PIC) in an industrial
project.
The controller would have to interface with 0 to 20mA analogue input and
output signals. Does anybody know of an IC(s) that does current-to-voltage
conversion and vica versa, perhaps with the use of one or two passive
components? I am looking for alternatives to using opamps.
Any suggestions/comments/advice appreciated.
Hennie Swanepoel
1997\07\02@060353
by
tjaart
|
Hennie Swanepoel wrote:
>
> I am thinking of using a microcontroller (perhaps a PIC) in an industrial
> project.
> The controller would have to interface with 0 to 20mA analogue input and
> output signals. Does anybody know of an IC(s) that does current-to-voltage
> conversion and vica versa, perhaps with the use of one or two passive
> components? I am looking for alternatives to using opamps.
>
> Any suggestions/comments/advice appreciated.
>
> Hennie Swanepoel
You probably mean 4mA to 20mA, don't you? A 250 ohm resistor gives you
1V to 5V.
Even though the 250 ohm is not standard E12, you can still get it in
very low
tolerances (0.1%).
--
Friendly Regards
Tjaart van der Walt
spam_OUTtjaartTakeThisOuT
wasp.co.za
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1997\07\02@073333
by
Ross McKenzie
At 11:36 2/07/97 GMT+200, you wrote:
>I am thinking of using a microcontroller (perhaps a PIC) in an industrial
> project.
>The controller would have to interface with 0 to 20mA analogue input and
>output signals. Does anybody know of an IC(s) that does current-to-voltage
>conversion and vica versa, perhaps with the use of one or two passive
>components? I am looking for alternatives to using opamps.
>
>Any suggestions/comments/advice appreciated.
>
>Hennie Swanepoel
>
Hello Hennie,
How about one resistor. V=I*R
50 ohms -> 1 volt full scale reading with 20 mA input.
Regards,
Ross McKenzie
Melbourne Australia
1997\07\02@090404
by
Harrison Cooper
typically.....its 4-20mA not 0 to 20 mA current loops. How about using
a precision resistor, then using an A/D to read the voltage drop across
the resistor. As current out, you can use an D/A and opamp to generate
the programmable current source.
1997\07\02@090819
by
Tom Handley
re: 4-20ma Current Loop Transmitter
Hennie, Burr-Brown has supplied these kind of ICs for years. Check out
their XTR105. You can reach them at:
800-548-6132
http://www.burr-brown.com
- Tom
At 11:36 AM 7/2/97 GMT+200, you wrote:
>I am thinking of using a microcontroller (perhaps a PIC) in an industrial
> project.
>The controller would have to interface with 0 to 20mA analogue input and
>output signals. Does anybody know of an IC(s) that does current-to-voltage
>conversion and vica versa, perhaps with the use of one or two passive
>components? I am looking for alternatives to using opamps.
>
>Any suggestions/comments/advice appreciated.
>
>Hennie Swanepoel
1997\07\02@134731
by
Hennie Swanepoel
Tjaart wrote:
> You probably mean 4mA to 20mA, don't you? A 250 ohm resistor gives you
> 1V to 5V.
> Even though the 250 ohm is not standard E12, you can still get it in
> very low
> tolerances (0.1%).
No, strangely enough 0 to 20mA is an old Siemens standard used for
process control (on at least some of the South-African power
stations). I would pefer not to use only a simple resistor
(preferably 50 ohm) since the accuracy of (subsequent) A/D conversion
would be deteriorate due the quantization effect etc. Also I need to
do the opposite: convert a voltage to a current in the 0 to 20 mA
range. The usual solution to both these problems involve using opamp
circuits. I was hoping that someone had come around to designing
IC's dedicated to current/voltage and voltage/current conversion.
Regards
Hennie
1997\07\02@172727
by
Guy Farebrother
|
----------
{Quote hidden}> From: Hennie Swanepoel <
.....D77190KILLspam
@spam@DVPNFS01.ESKOM.CO.ZA>
> To:
PICLIST
KILLspamMITVMA.MIT.EDU
> Subject: Re: Current to voltage- anyone know of an IC?
> Date: Wednesday, July 02, 1997 1:43 PM
>
> Tjaart wrote:
>
> > You probably mean 4mA to 20mA, don't you? A 250 ohm resistor gives you
> > 1V to 5V.
> > Even though the 250 ohm is not standard E12, you can still get it in
> > very low
> > tolerances (0.1%).
>
> No, strangely enough 0 to 20mA is an old Siemens standard used for
> process control (on at least some of the South-African power
> stations). I would pefer not to use only a simple resistor
> (preferably 50 ohm) since the accuracy of (subsequent) A/D conversion
> would be deteriorate due the quantization effect etc. Also I need to
> do the opposite: convert a voltage to a current in the 0 to 20 mA
> range. The usual solution to both these problems involve using opamp
> circuits. I was hoping that someone had come around to designing
> IC's dedicated to current/voltage and voltage/current conversion.
>
> Regards
> Hennie
If you are using a micro try looking at the AD420 or AD421 chips from
Analog Devices. They both allow you to generate a current from a 16 bit
digital value
Guy
1997\07\02@180418
by
trogers
Hennie Swanepoel wrote:
> I was hoping that someone had come around to designing
> IC's dedicated to current/voltage and voltage/current conversion.
Analog Devices has a series of IC's that handle this. I personally like
their stuff better than Burr Brown's. Poke around on the AD (
http://www.analog.com/ ) web site and look for the sensors & sensor
interfaces page. They have a nifty 4-20 or 0-20 ma serial dac, and I
know they used to have some isolation amps that handle current loop
inputs.
Somebody out there also has some loop powered isolation amps, but I
can't put my finger on who just now.
--Tom Rogers VP-R&D Time Tech Inc.
1997\07\04@121346
by
Gerhard Fiedler
|
At 19:43 02/07/97 GMT+200, Hennie Swanepoel wrote:
>Tjaart wrote:
>
>> You probably mean 4mA to 20mA, don't you? A 250 ohm resistor gives you
>> 1V to 5V.
>> Even though the 250 ohm is not standard E12, you can still get it in
>> very low
>> tolerances (0.1%).
>
>No, strangely enough 0 to 20mA is an old Siemens standard used for
>process control (on at least some of the South-African power
>stations). I would pefer not to use only a simple resistor
>(preferably 50 ohm) since the accuracy of (subsequent) A/D conversion
>would be deteriorate due the quantization effect etc.
I'm not sure whether I understand you here. How could a resistor based I-V
converter influence the subsequent ADC quantization? Just make sure that
the voltage at max current gives you something close to but lower than the
max voltage of your converter, and you are at the optimum you can get re
quantization.
Additionally, _every_ other solution (including opamps and, of course,
ready-made modules, which all are opamp based) depends on the same
principle (converting a current into a voltage by sending it trough a
resistor). No way around it, and rarely a need to use more than one
resistor in this case (which is also the optimum in both precision and
reliability).
If you have any special condition which makes it impossible to use it this
way, I'd really be interested to hear what it is.
>Also I need to
>do the opposite: convert a voltage to a current in the 0 to 20 mA
>range. The usual solution to both these problems involve using opamp
>circuits. I was hoping that someone had come around to designing
>IC's dedicated to current/voltage and voltage/current conversion.
An opamp is just this... you need only a few external resistors to do
either conversion (I->U 2-3, U->I 4 Rs), and all integrated modules I've
seen so far which do this are bigger than an opamp with some resistors.
(You can get down to a SOT-223 and 2-4 SMD resistors...) And they, of
course, are all based on opamps with a few resistors integrated in the same
package; you probably still need the one or other resistor to set the input
range. But really, I don't quite see how you can get it smaller and cheaper
and easier than with opamps.
-------------------------------------
Gerhard Fiedler <.....gerhardKILLspam
.....pobox.com>
S‹o Paulo - Brazil
1997\07\04@213206
by
Jeff Dickson
|
Gerhard,
_Every_ other solution does not depend on converting the current into a
voltage by sending it through a resistor. There are ways "around it." One
method is to measure the electric field around the wire; this is the
approach in noninvasive procedures. Other way is to dump the current into
a capacitor and integrate. This too eliminates the resistor, and is great
for applications that require small current measurements as it avoids large
resistance values. Burr-brown makes a couple of switched trans-impedance
amplifiers for this purpose.
Cheers,
-jeff
----------
From: Gerhard Fiedler <EraseMEGerhardspam_OUT
TakeThisOuTpobox.com>
To: PICLIST
spam_OUTmitvma.mit.edu
Subject: Re: Current to voltage- anyone know of an IC?
Date: Friday, July 04, 1997 9:12 AM
Additionally, _every_ other solution (including opamps and, of course,
ready-made modules, which all are opamp based) depends on the same
principle (converting a current into a voltage by sending it trough a
resistor). No way around it, and rarely a need to use more than one
resistor in this case (which is also the optimum in both precision and
reliability).
1997\07\05@155450
by
Dorin Dogaroiu
>I am thinking of using a microcontroller (perhaps a PIC) in an industrial
> project.
>The controller would have to interface with 0 to 20mA analogue input and
>output signals. Does anybody know of an IC(s) that does current-to-voltage
>conversion and vica versa, perhaps with the use of one or two passive
>components? I am looking for alternatives to using opamps.
>
>Any suggestions/comments/advice appreciated.
>
>Hennie Swanepoel
>
An idea for current to voltage : use LM3900 or equivalent. It's a
current input - voltage output quad OP amp single supply.
Dorin
---------------------------------
Dorin Dogaroiu
Research Institute for Computers
Bucarest, Romania
Email : @spam@dogaroiudKILLspam
pcnet.pcnet.ro
KILLspamddorinKILLspam
kappa.ro
---------------------------------
>
1997\07\05@160421
by
Gerhard Fiedler
|
At 18:29 04/07/97 -0700, Jeff Dickson wrote:
>_Every_ other solution does not depend on converting the current into a
>voltage by sending it through a resistor. There are ways "around it." One
>method is to measure the electric field around the wire; this is the
>approach in noninvasive procedures. Other way is to dump the current into
>a capacitor and integrate. This too eliminates the resistor, and is great
>for applications that require small current measurements as it avoids large
>resistance values. Burr-brown makes a couple of switched trans-impedance
>amplifiers for this purpose.
You're of course right in a general sense, but the original message was
talking about a 20mA loop, which is designed to feed into a resistor;
there's usually no need for a noninvasive measurement, and the currents
usually are not that small as to making it difficult to transform them into
a voltage easy to measure.
And with the cap charging method, just as with the electric field around
the wire (like a hall effect sensor), you finally get a voltage output --
which then has to be fed into an ADC, which usually uses some resistors
(amd maybe even opamps) in the analog signal path. I just didn't see the
point why trying to avoid a resistor in the signal path leading to the ADC
or trying to avoid opamps to generate the 20mA output current (always
taking into account that we're talking about a 20mA current loop designed
for load resistances in the range of probably up to around 1k).
BTW, how do you think that one adjusts the amplification of a trans-imp
amp? Most solutions I've seen use resistors, and so you just move the point
I was talking about (using resistors to transform current into voltage)
>from one place (at the input) to another (maybe in the feedback loop).
Which sometimes is of course _very_ appropriate (that's why they make them
:-), but again remembering the 20mA current loop...
And regarding precision, reliability and price I still have to see a better
solution than a resistor (for feeding an ADC) for measuring a 20mA loop.
-------------------------------------
Gerhard Fiedler <RemoveMEgerhardTakeThisOuT
pobox.com>
S‹o Paulo - Brazil
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