Post by thread:Addition (2 32-bit numbers) and Division

Hi, I need some help with adding two 32-bit numbers. What I have in mind: 8 bytes will be needed, 4 bytes for each of the numbers. My problem: How, do I use Status <C> , to automatically increment the next byte block, if there's a 1 carry? Then, I need to divide (the 32-bit number), by 2^24. To do this, type of a division, I will have to shift the numbers 24 times to the right, right? The result will be 8-bits. I will need about 8-bytes in doing this. My problem, once again, how/can I take advantage of the status flags (if they are needed?).[Sorry, I am quite new to programming]. Thanks in advance for your assistance. Regards, Saurabh

Saurabh Sinha wrote: > Then, I need to divide (the 32-bit number), by 2^24. Copy the most significant byte into the least-significant byte of your new number, any other more-significant bytes being already cleared (i.e., you have as you say, an 8-bit only result). -- Cheers, Paul B.

Check out MICROCHIP Application Note AN617 at http://www.microchip.com It will answer your questions on mul/div, multi byte addition and subtraction. Nikolai On Sunday, March 19, 2000 Saurabh Sinha wrote: {Quote hidden}> Hi, > I need some help with adding two 32-bit numbers. > What I have in mind: 8 bytes will be needed, 4 bytes for each of the > numbers. > My problem: How, do I use Status <C> , to automatically increment the next > byte block, if there's a 1 carry? > Then, I need to divide (the 32-bit number), by 2^24. To do this, type of a > division, I will have to shift the numbers 24 times to the right, right? The > result will be 8-bits. I will need about 8-bytes in doing this. My problem, > once again, how/can I take advantage of the status flags (if they are > needed?).[Sorry, I am quite new to programming]. > Thanks in advance for your assistance. > Regards, > Saurabh