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'[TECH]Solar cell efficiency research'
2011\11\18@043809 by cdb

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Not in the mood for typing so here is the link for anyone interested. Concerns Berkley National Laboratory.

http://littleurl.info/rq1
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cdb,   3/07/2009
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spam_OUTcolinTakeThisOuTspambtech-online.co.uk

2011\11\18@083824 by Vee Gee

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On Fri, Nov 18, 2011 at 4:38 AM, cdb <.....colinKILLspamspam@spam@btech-online.co.uk> wrote:
>  Not in the mood for typing

Been there, man.

2011\11\18@084005 by Vee Gee

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On Fri, Nov 18, 2011 at 4:38 AM, cdb <colinspamKILLspambtech-online.co.uk> wrote:
> http://littleurl.info/rq1

"If this energy is released as heat, it reduces the solar cell’s power
output, but if it is released as PHOTONS, the cell voltage is
increased, improving its power output."

Did he mean ELECTRONS instead of PHOTONS?

2011\11\18@085447 by smplx

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part 1 484 bytes content-type:text/plain; charset="Windows-1252" (decoded quoted-printable)



On Fri, 18 Nov 2011, Vee Gee wrote:

> On Fri, Nov 18, 2011 at 4:38 AM, cdb <.....colinKILLspamspam.....btech-online.co.uk> wrote:
>> http://littleurl.info/rq1
>
> "If this energy is released as heat, it reduces the solar cell’s power
> output, but if it is released as PHOTONS, the cell voltage is
> increased, improving its power output."
>
> Did he mean ELECTRONS instead of PHOTONS?

No

Regards
Sergio Masci

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2011\11\18@113437 by V G

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On 2011-11-18, at 8:58 AM, smplx <EraseMEsmplxspam_OUTspamTakeThisOuTallotrope.net> wrote:

> No
>
Rather blunt

2011\11\18@171850 by smplx

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part 1 1431 bytes content-type:text/plain; charset="iso-8859-7" (decoded quoted-printable)



On Fri, 18 Nov 2011, V G wrote:

> On 2011-11-18, at 8:58 AM, smplx <smplxspamspam_OUTallotrope.net> wrote:
>
>> No
>>
>
> Rather blunt.

Simple question simple answer. No slight intended.

>From the article:

    "Past efforts to boost the conversion efficiency of solar cells
     focused on increasing photon absorption in the cell. Absorbed photons
     produce electrons in the cell, but some of these electrons decay
     before being extracted from the cell and release their energy. If
     this energy is released as heat, it reduces the solar cellĒs power
     output, but if it is released as photons, the cell voltage is
     increased, improving its power output."

Say you have 100 photons hitting your cell and these release 100 electrons. Not all the electrons make it out of the cell, say 50 get converted to heat. The next 100 photons hitting the cell don't get converted to 100 electrons because the heated cell is now degraded. So lets say you now only get 40 electrons. Of these say 20 get converted to heat keeping the cell heated and reducing efficiency.

If instead of heating the cell the electrons that don't make it out get converted into other photons which escape without heating the cell then you don't get the same degradation.

So it makes sense that the author meant "photons"


Regards
Sergio Masci

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2011\11\18@180019 by Bob Axtell

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On 11/18/2011 6:58 AM, smplx wrote:
>
>
> On Fri, 18 Nov 2011, Vee Gee wrote:
>
>> On Fri, Nov 18, 2011 at 4:38 AM, cdb <@spam@colinKILLspamspambtech-online.co.uk> wrote:
>>> http://littleurl.info/rq1
>>
>> "If this energy is released as heat, it reduces the solar cell's power
>> output, but if it is released as PHOTONS, the cell voltage is
>> increased, improving its power output."
>>
>> Did he mean ELECTRONS instead of PHOTONS?
>
> No
>
> Regards
> Sergio Masci
>
>
Working in this area furiously, here is some clarity:

As the solar intensity increases, more electricity is
generated. However, as the PV junction gets hotter,
the amount of electricity generated drops.

So it behooves the user to somehow remove the heat
from the PV junction to keep temperatures down.

An efficient way to make use of the excess heat is
to remove the heat by circulating water behind the
panels, thus creating household "hot water" for almost
NO extra cost.

--Bob

2011\11\19@034202 by V G

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2011/11/18 smplx <KILLspamsmplxKILLspamspamallotrope.net>:
> Say you have 100 photons hitting your cell and these release 100 electrons.
> Not all the electrons make it out of the cell, say 50 get converted to heat.
> The next 100 photons hitting the cell don't get converted to 100 electrons
> because the heated cell is now degraded. So lets say you now only get 40
> electrons. Of these say 20 get converted to heat keeping the cell heated and
> reducing efficiency.
>
> If instead of heating the cell the electrons that don't make it out get
> converted into other photons which escape without heating the cell then you
> don't get the same degradation.
>
> So it makes sense that the author meant "photons"

Thank you, that's what I was looking for

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