Post by thread:[PIC] Re: newbie question

> The following code works > if(adc_result<0x0F) //if a/d count is below F then > ... > if(0x0F<=adc_result) //if a/d count is above or equal to F then > ... > > but this code does not > if(0x00<=adc_result<0x0F) //if a/d is below F then > ... > if(0x0F<=adc_result<=0xFF) //if a/d is below F then > ... > I'm sure I am overlooking something simple Since I read this list as a digest, I wouldn't be suprised if someone else has already answered, but... In C, the syntax "if ( adc_result < 0x0F )" is valid, while "if ( 0x0F <= adc_result <= 0xFF )" is not. A variable can only be compared to a single value, but you may make compound statements using logical operators ( && for AND and || for OR ) The valid syntax for what you're trying to write would be: if ( (adc_result >= 0x0F) && (adc_result <= 0xFF) ) Note that it's "&&" and not "&". Picking up a copy of "The C Programming Language" by K&R is a great idea if you're trying to learn C syntax. Good luck. -- Sean C. Malloy spam_OUTsmalloyTakeThisOuTio.com

> In C, the syntax "if ( adc_result < 0x0F )" is valid, while "if ( 0x0F <= > adc_result <= 0xFF )" is not. Ah ha.. Learn somethin new everyday.. So thats why whenever I tried to write(I've been coding in C/C++ for about 8 years) if(x=somefunc() != 0) { printf("hey"); } That it didnt work.. Figures its some syntax of C. -- andrew

It would work if you did this instead: if((x=somefunc()) != 0) { printf("AVR Rules."); } On 1/18/06, andrew kelley <.....leetslackerKILLspam@spam@gmail.com> wrote: {Quote hidden}> > > In C, the syntax "if ( adc_result < 0x0F )" is valid, while "if ( 0x0F > <= > > adc_result <= 0xFF )" is not. > > Ah ha.. Learn somethin new everyday.. So thats why whenever I tried to > write(I've been coding in C/C++ for about 8 years) > > if(x=somefunc() != 0) > { > printf("hey"); > } > > That it didnt work.. Figures its some syntax of C. > > -- > andrew > > -