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'[PIC] Re: bank allocation problem'
Marcelo, use the [PIC] subject tag if you want people to read your posts.
On Mon, Jun 1, 2009 at 8:29 AM, Marcelo Rodrigues <gmail.com> wrote: msrmail
Isaac Marino Bavaresco
Usually the compiler needs a few bytes of RAM for its own use (eg.:
interrupt state save, intermediate calculation results, etc).
Perhaps the compiler detects the lack of memory before it optimized and
removed its own unused internal variables.
It would be better if you leave some free memory in bank0, because the
common bank resides in the last 16 bytes of every bank and it is a more
Some compilers may not work unless there is some free memory in the
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How is your linker script looks like? That should tell you pretty much
everything what Isaac mentioned.
On Mon, Jun 1, 2009 at 6:54 PM, Isaac Marino Bavaresco <
yahoo.com.br> wrote: isaacbavaresco
> On Mon, Jun 1, 2009 at 8:29 AM, Marcelo Rodrigues <gmail.com> wrote: msrmail
>> Hi all,
>> I'm working with the PIC16F916, and according to the Datasheet (page 25)
>> it has the following memory banks:
>> Bank 0 = 96 bytes
>> Bank 1 = 80 bytes
>> Bank 2 = 80 bytes
>> Bank 3 = 96 bytes
Hm, I'm not sure you can use the last 16 bytes of Bank0
that way. It depends on how your tool does the allocation.
Those 16 bytes are part of the "share bank" or "unbanked
>> I've written a small program only with 4 arrays to fill the banks, but
>> the compiler return an error:
>> bank0 unsigned char volatile static var00;
>> bank1 unsigned char volatile static var01;
>> bank2 unsigned char volatile static var02;
>> bank3 unsigned char volatile static var03;
Do you realy need those arrays ?
Or is this some kind of "test" of the compiler ?
>> Error  double.c; 55. could not find space (96 bytes) for variable
>> However, if i set the bank 3 only with 80 bytes, it compiles succesfull
>> and says that I have 16 bytes free:
I had expected that to be Bank0, but again, do you
realy *need* those arrays ?
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