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'[PIC]:Please help with compiler error'
2003\04\12@150838 by Stephen D. Barnes

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Yup, I'm new to PIC assembly language!
**What am I doing wrong?**
When I compile my code which contains an "IF...ELSE...ENDIF", the  compiler (MPLab ver. 6.10) gives the following error:
 Error[108] E:\PIC\SALLYBOT.ASM 82 : Illegal character (,)
 The line of code it faults on follows (NOTE-the (,) character is NOT  in the code in question as the reported error would suggest).
 if (PB1 == 1) && (PB2 == 1)
 PB1 and PB2 are previously defined variables (portb,5 and portb,6).
I am attempting to test for a condition where both switches are  closed at the same time. I have tried this several different ways and  always get the same error.
Any insights?
 Regards,
Steve

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2003\04\12@151413 by Neil Bradley

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>  The line of code it faults on follows (NOTE-the (,) character is NOT
>  in the code in question as the reported error would suggest).
>
>  if (PB1 == 1) && (PB2 == 1)

That's a syntax error (if it's C):

  if ((PB1 == 1) && (PB2 == 1))

Is more like it.

-->Neil

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Neil Bradley            In the land of the blind, the one eyed man is not
Synthcom Systems, Inc.  king - he's a prisoner.
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2003\04\12@151849 by Ned Konz

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On Saturday 12 April 2003 12:00 pm, Stephen D. Barnes wrote:
> Yup, I'm new to PIC assembly language!
> **What am I doing wrong?**
> When I compile my code which contains an "IF...ELSE...ENDIF", the
>  compiler (MPLab ver. 6.10) gives the following error:
>
>  Error[108] E:\PIC\SALLYBOT.ASM 82 : Illegal character (,)
>
>  The line of code it faults on follows (NOTE-the (,) character is
> NOT in the code in question as the reported error would suggest).
>
>  if (PB1 == 1) && (PB2 == 1)
>
>  PB1 and PB2 are previously defined variables (portb,5 and
> portb,6).

No, they're not variables. They're text strings. So your statement
looks like:

if (portb,5 == 1) && (portb,6 == 1)

> I am attempting to test for a condition where both
> switches are closed at the same time. I have tried this several
> different ways and always get the same error.
> Any insights?

Beyond this, the "if" statement doesn't do what you think it does.
It's a directive to the assembler, *not* something that makes the PIC
evaluate a condition.

You want to do something considerably less readable:

       btfsc PB1
       goto nope
       btfsc PB2
       goto nope
yup:
       ; both 1 here
       bra done
nope:
       ; not both 1 here
done:

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2003\04\12@152306 by

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Perhaps you could post the full if-else-endif snippet ?
Error messages can sometimes point to the wrong line, that
is, where the error was detected, not where it was generated.
/Jan-Erik.

Stephen D. Barnes wrote:

When I compile my code which contains an "IF...ELSE...ENDIF", the
compiler (MPLab ver. 6.10) gives the following error:

Error[108] E:\PIC\SALLYBOT.ASM 82 : Illegal character (,)

The line of code it faults on follows (NOTE-the (,) character is NOT
in the code in question as the reported error would suggest).

if (PB1 == 1) && (PB2 == 1)

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