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'[OT:] Light bulb make square to sine wave'
2004\06\13@094749
by
Jinx
In response to
> X = 0.99999999 (repeating ad inifinitum)
>
> 10x = 9.999999999999 repeating
>
> 10x - x = 9x = 9.9999999 - .999999 = 9
>
> 9x = 9
>
> X = 1
I was sent
If a = b, then:
a^2 = a*b
a^2 - b^2 = (a*b) - b^2
(a-b)(a+b) = b(a - b)
(a+b) = b
Substitute the original a = b into the equation:
2b = b
2 = 1
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2004\06\13@111709
by
Wouter van Ooijen
2004\06\13@142745
by
res0qrqr
> > (a-b)(a+b) = b(a - b)
>
> If a == b the (a-b) terms in the above line are a mathematical black
> hole.
>
> Wouter van Ooijen
No, they are perfectly well-defined and obey all the laws
of mathematics... until you get to the very last line:
2b = b (everything's fine here)
therefore (NOT!)
2 = 1 (division by you-know-what error!)
Brian Aase
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2004\06\13@142749
by
Russell McMahon
> I was sent
>
> If a = b, then:
>
> a^2 = a*b
>
> a^2 - b^2 = (a*b) - b^2
> (a-b)(a+b) = b(a - b)
>
> (a+b) = b
>
> Substitute the original a = b into the equation:
>
> 2b = b
> 2 = 1
Took a few moments of staring :-)
(a-b)(a+b)=b(a-b)
BUT a=b so
(0)(2a) = b (0)
So either 0 = 0 (correct)
Or 2a=b is required for the 0's to be "the same"
But a=b, so no cigar.
RM
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2004\06\13@160822
by
Wouter van Ooijen
> > > (a-b)(a+b) = b(a - b)
> >
> > If a == b the (a-b) terms in the above line are a mathematical black
> > hole.
> >
> > Wouter van Ooijen
>
> No, they are perfectly well-defined and obey all the laws
> of mathematics.
Including the law that removing a factor of 0 at both sides of an
equation is not done?
Wouter van Ooijen
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2004\06\13@162051
by
William Chops Westfield
On Sunday, Jun 13, 2004, at 06:49 US/Pacific, Jinx wrote:
These are usually pretty similar...
> I was sent
>
> If a = b, then:
> a^2 = a*b
> a^2 - b^2 = (a*b) - b^2
> (a-b)(a+b) = b(a - b)
>
If a=b, then a-b = 0, and you can't divide by 0.
> (a+b) = b
>
> Substitute the original a = b into the equation:
> 2b = b
> 2 = 1
>
BillW
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2004\06\13@180001
by
Jinx
2004\06\15@091254
by
Jinx
> If a = b, then:
> a^2 = a*b
> a^2 - b^2 = (a*b) - b^2
> (a-b)(a+b) = b(a - b)
> (a+b) = b
> Substitute the original a = b into the equation:
> 2b = b
> 2 = 1
http://members.cox.net/mathmistakes/
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