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'[EE]:Maxim 472 / 4377 Current sense amps'
2002\11\21@071312
by
Goring, Steve
|
Hi list
Due to the discussion on the current sense amps a few days ago ( week or so
? )
I have some samples.
However my application calls for measuring > 10 amps at 24v which would
require a
sense resistor of 5 mOhm. How on earth (apart from a pcb track which I don't
think
I will be able to measure or make) do I get 5 mOhm ?
If anybody has worked with these IC's would they be kind enough to help me
out
with the resistor values for the above parameters ?
Thanks
Steve
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2002\11\21@082102
by
Alan B. Pearce
>However my application calls for measuring > 10 amps at
24v which would require a sense resistor of 5 mOhm. How
>on earth (apart from a pcb track which I don't think
>I will be able to measure or make) do I get 5 mOhm ?
This sounds like you are into territory where you start with a piece of
copper bar or tube as the sense resistor, and solder (or more likely bolt) a
couple on wires on it at appropriate tap points.
If you do take this route, then you may need to think about the temp co-eff
of the material used for the bar. If using solid bar, then you can probably
make it in a manner that minimises heat rise due to current flow.
Personally I would start with a piece of copper 1/2" water pipe, work out
from theoretical resistance of copper how far apart the tap points should
be, and solder a couple of wires on and give it a try.
Doing things this way also has the advantage that it is almost impossible to
burn out the current shunt :)
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2002\11\21@082726
by
Larry Bradley
|
I've used the MAX 472 to measure 100 amps, using a 0.5 milliohm sense
resistor. These are commercially available products commonly called
"shunts". Take a look at the Blue Seas Systems web site:
http://www.bluesea.com/Products/ME/ME.html
I'm sure there are a lot of other suppliers as well.
Shunts are typically rated as "amps for 50 mv", since they were originally
designed for use with analog meters, which typically required 50 mv for
full scale deflection. My shunt is 100 amps for 50 mv (thus the 0.5
milliohms). With the MAX 472, you can set the gain with the resistors to
basically any shunt value.
When I first started playing with measuring current, I didn't have a proper
shunt, so I made one out of a few feet of 8 or 10 gauge wire. Using copper
wire tables, I figured out about how long a piece I needed, and cut the
wire a bit longer. Then I put a measured 10 amps through the wire. Using a
digital voltmeter, I clipped on lead to one end of the "shunt" and clipped
a needle to the other end of a probe, and pushed it through the insulation
on the shunt in various places until the DVM read the proper voltage (in my
case I wanted 100 millivolts for 10 amps). Then I stripped a bit of
insulation off the shunt at that point and soldered a wire to it to use as
a sense wire.
The problem with using copper wire (or a copper trace) is that copper's
resistance changes with temperature - a shunt is built to have a
close-to-zero temperature coefficient. But for most hobby purposes, it
isn't a problem as long as the wire gauge used is large enough that the
current flowing through it does not cause it to heat up.
Larry
At 12:10 PM 11/21/2002 +0000, you wrote:
{Quote hidden}>Hi list
>
>Due to the discussion on the current sense amps a few days ago ( week or so
>? )
>I have some samples.
>
>However my application calls for measuring > 10 amps at 24v which would
>require a
>sense resistor of 5 mOhm. How on earth (apart from a pcb track which I don't
>think
>I will be able to measure or make) do I get 5 mOhm ?
>
>If anybody has worked with these IC's would they be kind enough to help me
>out
>with the resistor values for the above parameters ?
>
>Thanks
>
>Steve
Larry Bradley
Orleans (Ottawa), Ontario, CANADA
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2002\11\21@084843
by
Olin Lathrop
> Personally I would start with a piece of copper 1/2" water pipe, work
out
> from theoretical resistance of copper how far apart the tap points
should
> be, and solder a couple of wires on and give it a try.
A piece of #12 wire will be easier to deal with, and the much smaller
outer diameter will make it easier to compute the expected resistance.
Computing the resistance of a hollow tube between two point connections to
the outside of the tube is not a trivial matter.
*****************************************************************
Embed Inc, embedded system specialists in Littleton Massachusetts
(978) 742-9014, http://www.embedinc.com
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2002\11\21@094144
by
Katinka Mills
|
{Quote hidden}> -----Original Message-----
> From: pic microcontroller discussion list
> [
EraseMEPICLISTspam_OUT
TakeThisOuTMITVMA.MIT.EDU]On Behalf Of Goring, Steve
> Sent: Thursday, 21 November 2002 8:10 PM
> To:
PICLIST
spam_OUTMITVMA.MIT.EDU
> Subject: [EE]:Maxim 472 / 4377 Current sense amps
>
>
> Hi list
>
> Due to the discussion on the current sense amps a few days ago
> week or so
> ? )
> I have some samples.
>
> However my application calls for measuring > 10 amps at 24v which would
> require a
> sense resistor of 5 mOhm. How on earth (apart from a pcb track
> which I don't
> think
> I will be able to measure or make) do I get 5 mOhm ?
>
> If anybody has worked with these IC's would they be kind enough to help me
> out
> with the resistor values for the above parameters ?
>
> Thanks
>
> Steve
I usually calculate it with a length of cable, and place the two sense
points say 6" or so apart. Any good spec sheet for cable will give you the
resistance per 1000', so you could divide this down by 1000 to get the
resistance per foot.
Regards,
Kat.
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2002\11\21@104804
by
John Ferrell
Shunts are available on EBAY occasionally.
If you need to make a measurement and cannot wait to get the proper shunt, a
reasonable shunt can be patched together with a chunk of wire that can
handle the load and a sensitive meter. A meter that will read millivolts is
best. The innovative part is how to calibrate the reading. I generally:
1- measure the voltage drop on an existing cable already in the circuit.
2- Add a known load to the measured load & measure again
3- do the arithmetic
Don't forget to measure and consider the voltage each time.
Hopefully, you will have the ability to measure the load to be added
directly.
If you find the measurement varying with time you probably are heating the
cable you are using as a shunt.
Shunts are every where, just look around. A roll of house wiring, a piece of
pipe, an auto headlamp(lamps can be tricky), an electric heater, even an
aluminum cooking pot!
John Ferrell
6241 Phillippi Rd
Julian NC 27283
Phone: (336)685-9606
Dixie Competition Products
NSRCA 479 AMA 4190 W8CCW
"My Competition is Not My Enemy"
{Original Message removed}
2002\11\21@112945
by
Dave Tweed
|
Olin Lathrop <KILLspamolin_piclistKILLspam
EMBEDINC.COM> wrote:
> > Personally I would start with a piece of copper 1/2" water pipe, work out
> > from theoretical resistance of copper how far apart the tap points should
> > be, and solder a couple of wires on and give it a try.
>
> A piece of #12 wire will be easier to deal with, and the much smaller
> outer diameter will make it easier to compute the expected resistance.
This is true.
> Computing the resistance of a hollow tube between two point connections to
> the outside of the tube is not a trivial matter.
No, but that shouldn't even be an issue. Assuming he's building a proper
4-wire shunt, the potential around any circumference along the tube should
be the same. The load current should be applied at the centers of caps
attached to the ends of the tube. The sense wires can be tacked on at
points on the outside of the tube.
BTW, you can buy SMT milliohm shunts commercially, and they're not all that
expensive. You do need to be careful in your layout so that the sense
traces come directly off the shunt's pads and not from elsewhere along the
load current path.
Also, I have reverse-engineered some APC UPS units, and they just use a PCB
trace as the shunt. Of course, they aren't going for incredible accuracy;
they're more interested in just detecting overloads.
-- Dave Tweed
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2002\11\21@114400
by
William Chops Westfield
> However my application calls for measuring > 10 amps at
> 24v which would require a sense resistor of 5 mOhm. How
> on earth (apart from a pcb track which I don't think
> I will be able to measure or make) do I get 5 mOhm ?
My impression has been that at higher currents, you start looking at
current transformers or linear hall effect sensors...
Still, 10A doesn't seem like it would be THAT high; maybe you're just
looking at a sense amp designed for lower currents, and need to find
a different part...
BillW
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2002\11\21@114402
by
Peter L. Peres
You can buy a four-point shunt for 10A with 5mohms. You can also do this
with wire or PCB:
10A>========*=======*=======>10A
|tap1 |tap2
|fixed |move till calibrated
v v
to circuit
With a PCB you would have the trace to tap 2 not connected and fit a
jumper on prototypes. Later you will know how to patch the layout to yield
the correct shunt (it will still need calibration for accuracy).
Last, note that copper is a VERY poor choice for shunt material (high
temperature coeff.). Use nichrome or constantan instead.
Peter
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2002\11\21@115435
by
Peter L. Peres
On Thu, 21 Nov 2002, Alan B. Pearce wrote:
*>Doing things this way also has the advantage that it is almost impossible to
*>burn out the current shunt :)
Boy, are you wrong ;-). Need to do more work involving lead acid
batteries imho.
Peter
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2002\11\21@120452
by
Peter L. Peres
|
On Thu, 21 Nov 2002, Olin Lathrop wrote:
*>A piece of #12 wire will be easier to deal with, and the much smaller
*>outer diameter will make it easier to compute the expected resistance.
*>Computing the resistance of a hollow tube between two point connections to
*>the outside of the tube is not a trivial matter.
It is trivial for a shunt because the tube with uniform axial current flow
forms equipotential rings on it and the load (meter) impedance is very
high wrt the shunt.
You only want the resistance by length of the tube to be able to take a
long enough piece. That can be computed from ohms/sq and the weight of the
tube per unit length (easier than fumbling with wall thickness etc). All
you need is a kitchen scale and a resistivity table.
Me, I'd take a 1kW heater band from some appliance (toaster ?) and fold it
over N times. That's the proper material for shunts too (manganin or
constantan). Connection is best made by crimping. By the time you need to
reproduce this there will likely be other options.
Peter
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2002\11\21@125729
by
Alan B. Pearce
>Boy, are you wrong ;-). Need to do more work
>involving lead acid batteries imho.
Oh I'm quite aware of how beefy Lead Acid batteries are, and always take
great care around them because of this.
However I don't recall the original poster talking of an automotive app, but
may have missed it. OTOH it may just be that I'm too used to dealing with
29V space craft power supplies being imitated by 30A switchmodes which shut
down when anything goes awol.
But what I was getting at was the possibility of having a shunt that did go
o/c if something on the output side went wrong, would the chip stand a full
24V across the terminals that are supposed to have only millivolts across
it? I have not checked the data sheet, but ......
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2002\11\21@133623
by
Chris Hunter
You can make a suitable resistor with resistance wire, though you might have
problems at 10 A.
Chris
{Original Message removed}
2002\11\21@170329
by
Spehro Pefhany
|
At 12:10 PM 11/21/02 +0000, you wrote:
>However my application calls for measuring > 10 amps at 24v which would
>require a
>sense resistor of 5 mOhm. How on earth (apart from a pcb track which I don't
>think
>I will be able to measure or make) do I get 5 mOhm ?
You could buy two 10m Ohm parts and put them in parallel. Digikey has them
for (1W 0815 SMT parts from SSM) for about $2 each one-off; 1% tolerance.
If it's a volume application, you can get hairpin type open wire
parts for much, much less, but this could get you started.
Obviously layout counts at these levels. Use Kelvin connections.
If you insist on making home-made resistors, at least try to get ahold
of Constantan or Manganin wire which doesn't suffer from the rather large
(about +4000ppm/K) tempco of copper (and most other elemental metals).
Best regards,
Spehro Pefhany --"it's the network..." "The Journey is the reward"
RemoveMEspeffEraseME
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