>At 9:35 PM -0600 2/10/03, Josh Koffman wrote:
>>Second part is that the curve I'm looking for is not a straight
>>logarithmic curve. On a graph, it looks more like a stretched out "S".
>>The slope of the curve is more extreme in the center of the graph,
with
{Quote hidden}>>the top end and the bottom end flattening out. I'm trying to remember
>>the actual way of getting this curve. It has something to do with the
>>area under a sine curve, or the slope of the curve. I will check into
>>this further to figure it out.
>Philip Galanter wrote:
>I don't understand why you want to use an "S" curve. I guess on the
>high end at some point the eye runs out of range and no longer sees a
>linear increase in apparent brightness with an exponential increase
>in actual brightness. So for the entire range of vision the curve
>may look like an "S".
I have been watching this thread carefully, perhaps to apply something useful to a PIC controlled light dimmer. I understand
that an exponential curve should appear smoother to the eye. I found the spreadsheet techniques quite enlightening.
This topic has been for DC control, I'm considering how phase
control of a TRIAC for AC control would complicate the issue.
If I want to control a triac for AC light bulb control, wouldn't I then need to devise a lookup table that takes into account the integral of a sine wave, with the end result (hopefully) resembling a Log curve to appear "smooth" to the human eye?
I've been consumed with this for 24 hours now, and I'll readily admit that the math is beyond my education. I have done a few hours of web research and asked a few engineering friends if they can help, too.
My goal at this point is a method for computing a table of values that would describe the delay time after each zero crossing to fire the triac, in hopes that the light output from the bulb would _appear_ to brighten at a steady rate.(Log?) In my case, for 60Hz power.
For those better educated than myself, (that should be all of you) please pardon my poor description of the problem. Given that yesterday,
I couldn't even define "integral of a sine", I'm struggling along the best I can.
Lyle Hazelwood
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