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'[EE]: 555 with a duty cycle < 0.5 ??'
2001\03\14@173900 by Joan Ilari

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I have finished a IR proximity sensor with a 556 (<=> 2x555),
an IR led and an IS1U60. In order to save mA I need to reduce
the duty cycle of my 555's.

Somebody knows how to make a 555 oscillate with a duty cycle
smaller thab 0.5 ?

Note : duty cycle = ratio of the time duration when the ouput
pulse is high to the total period.

Thanxx !

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2001\03\14@174742 by Spehro Pefhany

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At 11:34 PM 3/14/01 +0100, you wrote:
>I have finished a IR proximity sensor with a 556 (<=> 2x555),
>an IR led and an IS1U60. In order to save mA I need to reduce
>the duty cycle of my 555's.
>
>Somebody knows how to make a 555 oscillate with a duty cycle
>smaller thab 0.5 ?
>
>Note : duty cycle = ratio of the time duration when the ouput
>pulse is high to the total period.

One way is to leave 7 open, connect 2 & 6 together & to cap,
as usual, and connect two resistors in series with diodes,
back to back between 2&6 and 3. This works better with
CMOS 555 and output lightly loaded.



6 & 2 --x----|<|----- R1 -----x--- 3
       |                     |
       x----|>|------R2 -----x

Ton = k * R1
Toff = k * R2

Duty cycle = Ton/(Ton+Toff) = k * (R1/(R1+R2))

So, just make R1 < R2 to get < 50% duty cycle

Best regards,
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2001\03\14@180647 by Tony Nixon

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Joan Ilari wrote:
>
> I have finished a IR proximity sensor with a 556 (<=> 2x555),
> an IR led and an IS1U60. In order to save mA I need to reduce
> the duty cycle of my 555's.
>
> Somebody knows how to make a 555 oscillate with a duty cycle
> smaller thab 0.5 ?
>
> Note : duty cycle = ratio of the time duration when the ouput
> pulse is high to the total period.
>
> Thanxx !

Just change the timing resistor values.

             R2
Duty =    ---------
          R1 + 2R2


I can't recall exactly, but I remember I used a 555 timing calculator on
the web some time ago.


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Tony

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2001\03\15@104301 by Wingate, F. Paine

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Nuts and Volts had an article in the December issue on using the 555.  I
recently put together a circuit to flash LED's at a low freg to alert
drivers when I'm on my bike.  Try putting a 1k resistor as R1 and then put a
pot as R2 and then you can vary R2 to change the freg as desired.

{Original Message removed}

2001\03\15@105524 by Roman Black

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Wingate, F. Paine wrote:
>
> Nuts and Volts had an article in the December issue on using the 555.  I
> recently put together a circuit to flash LED's at a low freg to alert
> drivers when I'm on my bike.  Try putting a 1k resistor as R1 and then put a
> pot as R2 and then you can vary R2 to change the freg as desired.


Someone already posted the correct "official"
solution, using diodes. A normal 555 astable only
goes from 50% to 100% duty, as it charges C1 through
R1 and R2 and discharges only via R2.

It is hard to get a shorter charge time. You will need
one diode across R2 to do it, so it charges via R1 and
diode, and discharges via R2 (and diode is reversed).

I've been playing with 555s since 10 years old. You
can also use a single inverter from a logic chip
to replace a 555 in 95% of circuits. For a 14pin chip
you can get 6 oscillators vs 2 in a 556.
-Roman

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2001\03\15@105742 by Nick Torenvliet

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I don't have them on me, but if you refer to the data sheets
for the 555 timer(at some place like http://www.onsemi.com) I'm sure you'll
find the sort of "standard application" for the 555.  It is
a circuit that consists of R1,R2 and C, manipulating the values
of R1 and R2 changes the duty cycle. I think the formula is
duty cycle = (R1+R2)/(R1+2*R2) so increasing the ration
R1:R2 will decrease the duty cycle.



{Original Message removed}

2001\03\15@120211 by Joan Ilari
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>  >
>  > Somebody knows how to make a 555 oscillate with a duty cycle
>  > smaller thab 0.5 ?
>  >
>
>  Just change the timing resistor values.
>
>                R2
>  Duty =    ---------
>             R1 + 2R2

As far as I know, the expression for the duty cycle of a 555 in astable
mode is :

           R1 + R2
Duty =    ---------
           R1 + 2R2

Thus, if R1 >> R2, duty -> 1 and if R2 >> R1, duty -> 0.5

Is this correct ?

Joan

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2001\03\15@121913 by Bill Westfield

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You can also simply "invert" the sense of your output - connect the load
between Vcc and pin3 instead of pin3 and Gnd...  Most 555s will sink as
much current at they source (but CMOS 555s don't tend to source as much as
they can sink.)

BillW

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2001\03\15@123543 by Joan Ilari

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>
>  I've been playing with 555s since 10 years old. You
>  can also use a single inverter from a logic chip
>  to replace a 555 in 95% of circuits. For a 14pin chip
>  you can get 6 oscillators vs 2 in a 556.
>  -Roman

You are completely right (this list is GREAT !)
For instance, in
www.users.dircon.co.uk/~doctron/chuckles.htm
there is exactly the circuit I want to build
(see the gated astable circuit) and I have two
spare nand gates for other uses.

Joan

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2001\03\16@042510 by Jane Ifurung

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this is easy. go to national ssemiconductor's site and
you can see the datasheet of 555. in the datasheet,
typical applications are found there. the duty cycle
depends on the external components (can't remember the
formula).

jane

--- Nick Torenvliet <.....torenvlietKILLspamspam.....SYMPATICO.CA> wrote:
{Quote hidden}

> {Original Message removed}

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